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D2D模式选择仿真

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发表于 2023-12-19 05:04:54 | 显示全部楼层 |阅读模式
简单的解决了资源分配的问题,现在假设有3个可用信道,一个蜂窝用户只允许一个d2d对用户复用资源(复用方式是复用距离最远的蜂窝用户信道,暂时没有考虑干扰问题),那么这3个信道最多可以容纳6个用户(3个蜂窝用户,3对d2d用户)同时进行正常通信,其中蜂窝用户以60%的概率生成,d2d用户以40%的概率生成,且都服从指数分布。如果没有可用信道,则用户进入呼阻状态。呼阻用户持续一段时间后消失

文件列表:
CUEtoD2D_interferencePathLoss.m
Cal_next_point.m
Check_Resttime.m
D2DPathLoss.m
D2DtoBS_inteferencePathLoss.m
Draw_drop_cdf.asv
Draw_drop_cdf.m
Draw_drop_cell_cdf.asv
Draw_drop_cell_cdf.m
Draw_drop_d2d_cdf.m
Draw_drop_thr_cdf.m
Draw_drop_thr_mesure.asv
Draw_drop_thr_mesure.m
Draw_mesurements.asv
Draw_mesurements.m
Draw_points.m
Draw_thr_cdf.asv
Draw_thr_cdf.m
Drawside.m
Hungarian.m
Powerschedule_deduce.m
Untitled.m
Untitled2.m
cal_Throughput.m
cal_blocknum.m
cal_thr_cell.m
cal_thr_d2d.m
cal_throughput_delay.asv
cal_throughput_delay.m
cal_throughput_delay_inspire.asv
cal_throughput_delay_inspire.m
cal_throughput_improve.asv
cal_throughput_improve.m
cal_throughput_random.m
cal_two_delay.m
calcolor.m
calnun.m
cel_D2DtoBS_inteferencePathLoss.m
cellInstall.m
checkchannel.m
checkpoint.m
checkpoint_d2d.m
codechange.m
draw_back.m
draw_block.m
draw_block_cell.m
draw_block_d2d.m
draw_drop.m
draw_figure.m
draw_jump.m
find_mult_channel_cell.m
find_mult_channel_d2d.m
findpoint_b.m
findpoint_b_2.m
generateChannelInfo.m
generateLargeScaleChannel.m
generateReceptpower.m
generateSINR.m
generate_throughtput.m
generatethr.asv
generatethr.m
generatetime.m
generatev.m
imagtest.jpg
init_r_queue.asv
init_r_queue.m
main.m
makepoint.m
makepoint_d2d.m
mymain.asv
mymain.m
nextpoint.m
okumura.m
poisson.m
qMain.m
queue.m
readme.txt
releasePD.m
releasePD_d1.m
releasePD_d2.m
releasePD_d2d.m
releasePathloss.m
releasech.m
releasech_d2d.m
resource_alloc.asv
resource_alloc.m
simConfig.m
simDisplay.m
sum_throughput_Delay.asv
sys_initiate.asv
sys_initiate.m
userInstall.m
userMovement.m
user_d2d.m
user_d2d_alloc.asv
user_d2d_alloc.m
user_guide.m
z_Untitled4.m
z_Untitled5.m
z_Untitled6.m
z_Untitled7.m
z_Untitled8.m
z_Untitled9.m
z_move_user.m
说明.txt

运行例图:
01.gif


D2D模式选择仿真.zip (146.54 KB, 下载次数: 0, 售价: 30 积分)


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